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CGP EDU Academic Team
Published on: August 13, 2026
In hydrogen atom, the de Broglie wavelength of an electron in the second Bohr orbit is [Given that Bohr radius,
]
Text Solution
Verified by ExpertsThe correct answer is:
B
Bohr radius,
pm
pm
The angular momentum of an electron in a given
stationary state can be expressed as in equation,

de‐Broglie equation
(i)
... (ii)
From equations, (i) and (ii), we get 
Putting the value of
pm
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